выпадающее меню

#
выпадающее меню
Всем известное меню:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE xsl:stylesheet>
<xsl:stylesheet version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:hostcms="http://www.hostcms.ru/"
        exclude-result-prefixes="hostcms">
        <xsl:output xmlns="http://www.w3.org/TR/xhtml1/strict" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN" encoding="utf-8" indent="yes" method="html" omit-xml-declaration="no" version="1.0" media-type="text/xml"/>

        <xsl:template match="/">
                <xsl:apply-templates select="/shop"/>
        </xsl:template>

        <!-- Шаблон для магазина -->
        <xsl:template match="/shop">
        
                <div class="titleH1">
                        <xsl:value-of disable-output-escaping="yes" select="name"/>
                </div>
                <ul class="blockGroupsList">
                        <xsl:apply-templates select="shop_group"/>
                </ul>
        </xsl:template>

        <!-- Шаблон для групп товара -->
        <xsl:template match="shop_group">
                <xsl:variable name="current_group_id" select="/shop/current_group_id"/>
                <li>
                        <xsl:variable name="li_class">
                                <xsl:if test="position() = last()"> last</xsl:if>
                                <xsl:if test="$current_group_id = @id or count(.//shop_group[@id=$current_group_id])=1"> current</xsl:if>
                        </xsl:variable>
                        <xsl:attribute name="class">
                                <xsl:value-of select="normalize-space($li_class)"/>
                        </xsl:attribute>
                        
                        <a href="{url}">
                                 <xsl:if test="$current_group_id = @id or count(.//shop_group[@id=$current_group_id])=1">
                                        <xsl:attribute name="class">
                                           <xsl:text>current</xsl:text>
                                        </xsl:attribute>
                                 </xsl:if>
                                <span></span><xsl:value-of disable-output-escaping="yes" select="name"/>
                        </a>

                        <!-- Если есть подгруппы -->
                        <xsl:if test="shop_group">
                                <ul class="blockGroupsSubList">
                                        <xsl:apply-templates select="shop_group"/>
                                </ul>
                        </xsl:if>
                </li>
        </xsl:template>
</xsl:stylesheet>


Только вот нужно разделить категории и субкатегории, для того, что бы присвоить отдельный css, как категории, так и субкатегории.
#
Re: выпадающее меню
подправлю себя
Вот тут будет так
                        <!-- Если есть подгруппы -->
                        <xsl:if test="shop_group">
                                <ul>
                                        <xsl:apply-templates select="shop_group"/>
                                </ul>
                        </xsl:if>


нашёл на форуме решение для v5 http://www.hostcms.ru/forums/22/1997/
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